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  #21  
Old   
Jeff Strickland
 
Posts: n/a

Default Re: wheel circumference - 11-05-2009 , 10:48 PM






"Tegger" <invalid (AT) invalid (DOT) inv> wrote

Quote:
"badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in
news:xn0ghau681ojn70000 (AT) news (DOT) albasani.net:

Tegger, 11/5/2009,4:03:51 PM, wrote:

"badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in
news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net:

Jeff Strickland wrote:

The OP wants a larger sidewall for some reason, not a smaller
one. (I don't get the logic he's using, but it's not my
decision.)

I don't want anything changed on my car. I was just wondering if
there is a difference between tires with thin sidewalls and those
with very wide sidewalls when it comes to odometer/speedometer
readings. And I'm not talking about one inch differences, more
like 45s vs. 85s.

After you guys work out all this technical minutia let me know what
the consensus is.





You'll never get "consensus".

The fact is:
Given a specific sidewall height and overall tire diameter, if you
change ONLY the sidewall height (bigger wheel), you WILL change the
rolling circumference.

If you go from a 60 to a 50, you probably won't notice the
difference. If you go from an 80 to a 45, there would be a big
difference.

So will the wheel with the 80 tire rotate more or less than the wheel
with the 45? Which one will show more than the correct speed and
which one will show less?



The OEM wheel, tire size, and speed rating will be closest to the
manufacturer's intended speedometer calibration.


That is not entirely true. For example, the Camry has several different tire
sizes that can be fitted by virtue of the different trim levels and various
option packages. The speedometer is not calibrated for each different size
of tire package, it is calibrated for the largest tire package. Smaller
tires will have greater speedometer error than the larger tires. If the base
model Camry gets a 195 / 60 x 15, the fully loaded can have a 215 / 45 x 17,
and the diameter of the tire is different by less than one-half inch. The
speedo calibration can be identical across the model line, meaning that one
could buy a base model car then get upgrade tires and wheels and still use
the same speedo.



Quote:
When it comes to aftermarket, I wish I could pin that question down for
you, but I can't. The answer depends on the actual rolling circumference
that each tire describes when loaded the way your car will load it.

One maker's 225/45-16 won't necessarily measure the same actual unloaded
diameter as another maker's 225/45-16. And those tire-shop tire-size
equivalency charts are fraught with uncertainty on account of that.

But: Given two differently-seriesed tires with identical unloaded
circumferences, the one with the shorter sidewall will have the larger
rolling circumference and the lower speedometer reading.

The upshot is that the difference will likely not be enough for anybody
to notice unless he's very specifically looking for that difference.
Even the cops recognize that, which is partly why they give you 5mph
grace (or more depending on the jurisdiction) before whacking you.

That's certainly true. The differences you are telling us about are there,
maybe, but utterly insignificant UNLESS one tire is different than the rest.
The small difference could be enough to trigger the Low Pressure Monitor if
said monitor derives its information from the speed sensors.

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  #22  
Old   
Tegger
 
Posts: n/a

Default Re: wheel circumference - 11-06-2009 , 06:55 AM






"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in
news:hd069m$b9l$1 (AT) news (DOT) eternal-september.org:

Quote:
"Tegger" <invalid (AT) invalid (DOT) inv> wrote in message
news:Xns9CBAE1FF91E2Etegger (AT) 208 (DOT) 90.168.18...




The OEM wheel, tire size, and speed rating will be closest to the
manufacturer's intended speedometer calibration.



That is not entirely true. For example, the Camry has several
different tire sizes that can be fitted by virtue of the different
trim levels and various option packages. The speedometer is not
calibrated for each different size of tire package, it is calibrated
for the largest tire package. Smaller tires will have greater
speedometer error than the larger tires. If the base model Camry gets
a 195 / 60 x 15, the fully loaded can have a 215 / 45 x 17, and the
diameter of the tire is different by less than one-half inch. The
speedo calibration can be identical across the model line, meaning
that one could buy a base model car then get upgrade tires and wheels
and still use the same speedo.


But they're all OEM, which is my point.





--
Tegger

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  #23  
Old   
Tegger
 
Posts: n/a

Default Re: wheel circumference - 11-06-2009 , 07:08 AM



"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in
news:hd05hr$6ok$1 (AT) news (DOT) eternal-september.org:

Quote:
"Tegger" <invalid (AT) invalid (DOT) inv> wrote in message
news:Xns9CBAE381511EEtegger (AT) 208 (DOT) 90.168.18...
"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in
news:hd044q$sph$1 (AT) news (DOT) eternal-september.org:


"badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in message
news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net...
Jeff Strickland wrote:

The OP wants a larger sidewall for some reason, not a smaller one.
(I don't get the logic he's using, but it's not my decision.)

I don't want anything changed on _my_ car. I was just wondering if
there is a difference between tires with thin sidewalls and those
with very wide sidewalls when it comes to odometer/speedometer
readings. And I'm not talking about one inch differences, more like
45s vs. 85s.

After you guys work out all this technical minutia let me know what
the consensus is.




The short answer is, no, there is no difference.

The long asnwer is that the overall diameter has to be the same for
the short answer to be true. For example, my truck has a 265/75x16.
I could go to a 265/35x20 and the tire should be the same overall
diameter, therefore no affect on the speedo.




Supposing the two sizes have identical unloaded diameters, the 35
will have
the larger rolling circumference and the slower speedometer reading.



NOT true. Well, not entirely true.

For every inch increase in the rim, the aspect ratio is decreased 5%.
The result is a overall diameter, or radius, or circumference
(depending on the specy you prefer) will be virtually identical. The
difference -- if done on all four corners -- is insignificant. There
will be a small change to the speedometer -- a change measured in
single digit percentages.


As I said all along. The point is that it is unlikely that there will be
NO change.

Another example for illustration:

Assume a tire with 23.21" diameter (my 195/60-14). The sidewall of that
tire measures 4.6". The front tires drop about .875" at the contact
patch. That's about 19%.

Now assume a tire of the same diameter, but a hypothetical size of
195/35-18. This gives the sidewall a height of 2.7". Now imagine that
this same tire has a drop of .875" at the contact patch. That's
/one-third/ of the sidewall height of only 2.7"!

NO 35-series tire drops 7/8" at the contact patch. It cannot. Any owner
of that tire would be convinced his tire was flat! And this means the
effective rolling circumference of such a tire would be /larger/ than
the original 195/60-14, giving a slower speedometer reading..




Quote:
The speedometer would be more sensitive to the circumference, but
since circumference is calculated by diameter X pi, or radius X 2 X
pi, then all are the same.

I assume proper inflation, and ignore any argument that assumes
improper inflation. Improper inflation causes a variance, and the
variance is measured by the speed sensors, not the speedometer.



If the wheel is turning at a speed other than what the speedometer is
expecting, the speedometer will reflect that. Period. It may not be
enough to notice in everyday driving, but it will be reflected.

ABS-based speed sensors only track DIFFERENCES between wheels, not
absolute speeds. And if a lower pressure makes a difference to the ABS,
it will also make a difference to the speedometer, provided the lower
pressure tire is on the wheel that's on the "solid" side of the diff.


--
Tegger

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  #24  
Old   
C. E. White
 
Posts: n/a

Default Re: wheel circumference - 11-06-2009 , 08:36 AM



"Tegger" <invalid (AT) invalid (DOT) inv> wrote

Quote:
"C. E. White" <cewhite3 (AT) mindspring (DOT) com> wrote in news:hcur0a$o5e$1
@news.eternal-september.org:




How can what you are saying be true? Look at it a different
way...every time the tire goes through a revolution, there is
apporximately a one to one relationship between the tire and the
road
surface (every part of the tire contact the road). One revolution
of
the tire will move the car forward by the circumfrence of the tire.



The /working/ circumference, which changes with all sorts of
factors,
pressure, weight, sidewall height.

As I said before, ABS-based low-pressure warning systems
_could not work_ unless this was true.
Very ture, but they work by comparing the response of similar tires
and take a relatively long time to figure out that one is runnnig at a
much lower pressure than the others (miles of driving). Lots of thing
affect the number of revolutions per mile for a tire, but most are
minor. Even the speed of the car has an effect. My only point is, you
can't treat a tire like a hard rubber wheel. The loaded radius
(distance from the axle centerline to the ground) is not the most
significant factor in determining the rolling diameter of the tire.


Quote:
If
it doesn't you have to have slip (which will be true if you spin
the
tires, but is a negligible factor if you are cruising straight
ahead
on a level road at a moderate sped).



Not so. It's called "scrub" and is the reason tires wear even in a
straight-ahead, steady-state position.



The fact that the tire flattens
out at the road surface doesn't change this.



But that makes /all/ the difference.



Of course rubber is
flexible and can stretch/shrink, which is why the really important
circumfrence is the circumfrence of the steel belts inside the
tire.
The treads area can stretch and flex (think about how tank treads
move) but the steel belt stretchs only by tiny amounts. Unless the
tire is so underinflated that the tire assumes a concave shape at
the
road surface, the effective rolling radius is not significantly
dependednt on the distance from the road to the wheels center axis.



Then how can an ABS-based warning system work if it cannot depend on
changes in working radius? And monitoring changes in rolling
circumference due to changed working radius _IS_ how such systems
operate.
I did not say that there was no effect, just that it is a major
effect. The ABS tire monitoring systems compare the response of the
tires. A tire with a much lower pressure than the others will on
average have a different rolling radius, but it is a very small
difference. Thise systems takes miles to figure out a tire is
underinflated.

Quote:
Like most real world things, there are other factors that come into
play, so I don't doubt that there is some effect on revolutions per
mile related to tires of the same outside diameter with different
inner diameters (i.e., wheel size), but the I don't think the
loaded
radius is the prime reason.

One more thing to think about. If you are right, where does the
extra
tire go?



Where did that 1/4" go? I don't know. I suspect there's a minuscule
stretch or displacement around the unloaded portion of the tire. But
in
order to confirm that, I'd need to jack the wheel off the ground and
take some really careful measurements both loaded and unloaded.

My contact patch is about 4.25" front-to-back (about 45deg of
rotation).
On my tire, a line traced from front-to-back on that flat spot is
about
a quarter-inch shorter than the curve would be if the tire was not
flattened by the load.

If that 1/4" were distributed evenly around the unloaded portion of
my
tire, each of the 315 degrees of unloaded tire would have to
displace or
stretch about .0008", which is plausible. Plus some of the
distortion
would be compressed into the flat spot, so the .0008 might be an
overestimate.



result inthe car moving forward by a distance equal to the loaded
radius of the tire times 2 times pi. But the actual circumfrence of
the tire is the unloaded diameter of the tire times pi. Since 2
times
the loaded radius of the tire is less than the unloded diameter of
the
tire times pi, this implies something is happening witht he "extra"
circumfrecne in your senario. Where is it going? You might convince
me
that the rubber portion is stretching and shrinking to accomodate
your
theory, but what is happenign with the steel belt in the tire?


Well, I have one guess: The steel belt is a woven assembly with the
wires on a bias. It's possible the weave distorts under compression
and
extension, much like rope, cloth or window screen can.




One last analogy - think conveyor belt.....

Did you look at the chart I included with the prior note?



I did, but the chart misses the point.
The point was that the rolling circuimference of tires with similar
outside diamters but different rim diamters are usually very close..

Quote:
My trump card is ABS-based low-pressure warning systems. I know for
a
fact that they work by sensing a low-pressure tire spinning faster
than
one with higher pressure, which can ONLY happen if the working
radius
(and circumference) can shrink and grow on an otherwise inextensible
tire.
Again, I agree that these ABS systems work by detecting changes in the
rolling radius of the tire, but the effects are very small and the
system take miles to figure out that the tires are different. The
rolling radius is affected by many things, temeprature, speed,
inflation pressure, even the particular road surface, but the ABS
based systems work by comparing tires to other tires on the car. They
can detect samll changes that affect one tire comapred to the others.
Therefore the small effect on the rolling radius due to a large change
in air pressure (>20% decrease) is detectable by these sysems

I am sure you are greatly over emphasizing the contribution of the
loaded radius on the rolling diamter of tires, but don't know of any
other effective arguements. Maybe an experiment would convince you. If
you have the time, measure the loaded radius, mark the tire, move the
car for 100 revolutions of the tire, and then measure the distance
moved...You will find that it moved a significantly greater distance
than 2 x pi x loaded radius x 100.

Ed

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  #25  
Old   
Jeff Strickland
 
Posts: n/a

Default Re: wheel circumference - 11-06-2009 , 12:51 PM



"Tegger" <invalid (AT) invalid (DOT) inv> wrote

Quote:
"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in
news:hd05hr$6ok$1 (AT) news (DOT) eternal-september.org:


"Tegger" <invalid (AT) invalid (DOT) inv> wrote in message
news:Xns9CBAE381511EEtegger (AT) 208 (DOT) 90.168.18...
"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in
news:hd044q$sph$1 (AT) news (DOT) eternal-september.org:


"badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in message
news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net...
Jeff Strickland wrote:

The OP wants a larger sidewall for some reason, not a smaller one.
(I don't get the logic he's using, but it's not my decision.)

I don't want anything changed on _my_ car. I was just wondering if
there is a difference between tires with thin sidewalls and those
with very wide sidewalls when it comes to odometer/speedometer
readings. And I'm not talking about one inch differences, more like
45s vs. 85s.

After you guys work out all this technical minutia let me know what
the consensus is.




The short answer is, no, there is no difference.

The long asnwer is that the overall diameter has to be the same for
the short answer to be true. For example, my truck has a 265/75x16.
I could go to a 265/35x20 and the tire should be the same overall
diameter, therefore no affect on the speedo.




Supposing the two sizes have identical unloaded diameters, the 35
will have
the larger rolling circumference and the slower speedometer reading.



NOT true. Well, not entirely true.

For every inch increase in the rim, the aspect ratio is decreased 5%.
The result is a overall diameter, or radius, or circumference
(depending on the specy you prefer) will be virtually identical. The
difference -- if done on all four corners -- is insignificant. There
will be a small change to the speedometer -- a change measured in
single digit percentages.



As I said all along. The point is that it is unlikely that there will be
NO change.

Another example for illustration:

Assume a tire with 23.21" diameter (my 195/60-14). The sidewall of that
tire measures 4.6". The front tires drop about .875" at the contact
patch. That's about 19%.

Now assume a tire of the same diameter, but a hypothetical size of
195/35-18. This gives the sidewall a height of 2.7". Now imagine that
this same tire has a drop of .875" at the contact patch. That's
/one-third/ of the sidewall height of only 2.7"!

NO 35-series tire drops 7/8" at the contact patch. It cannot. Any owner
of that tire would be convinced his tire was flat! And this means the
effective rolling circumference of such a tire would be /larger/ than
the original 195/60-14, giving a slower speedometer reading..





The speedometer would be more sensitive to the circumference, but
since circumference is calculated by diameter X pi, or radius X 2 X
pi, then all are the same.

I assume proper inflation, and ignore any argument that assumes
improper inflation. Improper inflation causes a variance, and the
variance is measured by the speed sensors, not the speedometer.




If the wheel is turning at a speed other than what the speedometer is
expecting, the speedometer will reflect that. Period. It may not be
enough to notice in everyday driving, but it will be reflected.

ABS-based speed sensors only track DIFFERENCES between wheels, not
absolute speeds. And if a lower pressure makes a difference to the ABS,
it will also make a difference to the speedometer, provided the lower
pressure tire is on the wheel that's on the "solid" side of the diff.




I don't see that it matters if all tires are the same equivelent of the
original specification, or that they are all the same non-equivelent --
physical fitment issues aside.

ABS does not look at different speeds of the tires, it looks at some tires
turning and some tires not turning, it makes the not-turning tires turn. The
speedo would not care about one tire turning at a different speed, ever.

But none of this is in the realm of answering the OP's question. His
question was not framed very well, but that's another discussion all by
itself.

In the example of the 195/60x14 and the 195/35x18, the sidewall goes from
4.6 to 2.7 inches, but the tire diameter goes from 23.2 to 23.4, and the
tire circumference goes from 72.9 to 73.4, and the revolutions per mile go
from 869 to 863.

It's possible that in such a small sidewall that the pressure monitor might
not work very well, or at all, if it's based on feed from the speed sensors.
This might be an undesirable affect.

But the speedo would be unafftected for all practical purposes. Since the
new tire is miniscually larger, then the speedo would slow a tiny amount --
a current reading of 70 might be an actual speed of 66 and the new reading
of 70 might be an actual speed of 68, which is a desirable change as opposed
to an undesirable one.

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  #26  
Old   
Tegger
 
Posts: n/a

Default Re: wheel circumference - 11-07-2009 , 05:44 PM



"C. E. White" <cewhite3 (AT) mindspring (DOT) com> wrote in news:hd18tv$dr6$1
@news.eternal-september.org:


Quote:
I am sure you are greatly over emphasizing the contribution of the
loaded radius on the rolling diamter of tires, but don't know of any
other effective arguements. Maybe an experiment would convince you. If
you have the time, measure the loaded radius, mark the tire, move the
car for 100 revolutions of the tire, and then measure the distance
moved...You will find that it moved a significantly greater distance
than 2 x pi x loaded radius x 100.


I must be nuts, because I actually went out and tested your theory (and
mine). I hope you do me the grace of actually reading this, because I did
perform the test instead of being Usenet-snarky and telling you to go and
do the test yourself.

After making a gauge with corrugated cardboard, I discovered that the
unloaded diameter of both front and rear tires is 23.25" dead-on.

23.25" x 3.14159 = 73.04" unloaded circumference.

Tire pressures at time of test were all the same, 31 lbs (checked hot).

On a flat, newly paved industrial parking lot, I marked the tires (and the
lot) with chalk. Leaning out the window, I then slowly rolled the car so
that the mark on the left tire described ten revolutions, coming down to
the very bottom again. That covered almost 60 feet (100 revolutions was not
practical for me.)

I did this four times each, for the front and then for the rear tires (both
sides). The results were very consistent.

The results?
Actual distance covered for the fronts: 704.5"
Actual distance covered for the rears: 708.5"

Now, how about the "loaded" radius?
For the front left, it's 11.75", which gives a circumference of 67.54"
However, that tire actually covered 70.45" per rev, not 67.54". But at the
same time it was not covering 73.04" either.

For the rear left, the loaded radius is 11.0625". This gives a
circumference of 69.51". That tire actually rolled 70.85" in the test.

Let's summarize, as percent reduction from unloaded to loaded:
Front hypothetical rolling circum based on loaded radius: 7.5% less
Front actual rolling circum based on test result: 3.55% less
Rear hypothetical rolling circum based on loaded radius: 4.8% less
Rear actual rolling circum based on test result: 3% less

Looks like the fronts split the difference between unloaded and loaded, and
the rears were affected pretty close to what I theorized.




--
Tegger

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