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#21
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"badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in news:xn0ghau681ojn70000 (AT) news (DOT) albasani.net: Tegger, 11/5/2009,4:03:51 PM, wrote: "badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net: Jeff Strickland wrote: The OP wants a larger sidewall for some reason, not a smaller one. (I don't get the logic he's using, but it's not my decision.) I don't want anything changed on my car. I was just wondering if there is a difference between tires with thin sidewalls and those with very wide sidewalls when it comes to odometer/speedometer readings. And I'm not talking about one inch differences, more like 45s vs. 85s. After you guys work out all this technical minutia let me know what the consensus is. You'll never get "consensus". The fact is: Given a specific sidewall height and overall tire diameter, if you change ONLY the sidewall height (bigger wheel), you WILL change the rolling circumference. If you go from a 60 to a 50, you probably won't notice the difference. If you go from an 80 to a 45, there would be a big difference. So will the wheel with the 80 tire rotate more or less than the wheel with the 45? Which one will show more than the correct speed and which one will show less? The OEM wheel, tire size, and speed rating will be closest to the manufacturer's intended speedometer calibration. |
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When it comes to aftermarket, I wish I could pin that question down for you, but I can't. The answer depends on the actual rolling circumference that each tire describes when loaded the way your car will load it. One maker's 225/45-16 won't necessarily measure the same actual unloaded diameter as another maker's 225/45-16. And those tire-shop tire-size equivalency charts are fraught with uncertainty on account of that. But: Given two differently-seriesed tires with identical unloaded circumferences, the one with the shorter sidewall will have the larger rolling circumference and the lower speedometer reading. The upshot is that the difference will likely not be enough for anybody to notice unless he's very specifically looking for that difference. Even the cops recognize that, which is partly why they give you 5mph grace (or more depending on the jurisdiction) before whacking you. |
#22
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"Tegger" <invalid (AT) invalid (DOT) inv> wrote in message news:Xns9CBAE1FF91E2Etegger (AT) 208 (DOT) 90.168.18... The OEM wheel, tire size, and speed rating will be closest to the manufacturer's intended speedometer calibration. That is not entirely true. For example, the Camry has several different tire sizes that can be fitted by virtue of the different trim levels and various option packages. The speedometer is not calibrated for each different size of tire package, it is calibrated for the largest tire package. Smaller tires will have greater speedometer error than the larger tires. If the base model Camry gets a 195 / 60 x 15, the fully loaded can have a 215 / 45 x 17, and the diameter of the tire is different by less than one-half inch. The speedo calibration can be identical across the model line, meaning that one could buy a base model car then get upgrade tires and wheels and still use the same speedo. |
#23
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"Tegger" <invalid (AT) invalid (DOT) inv> wrote in message news:Xns9CBAE381511EEtegger (AT) 208 (DOT) 90.168.18... "Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in news:hd044q$sph$1 (AT) news (DOT) eternal-september.org: "badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in message news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net... Jeff Strickland wrote: The OP wants a larger sidewall for some reason, not a smaller one. (I don't get the logic he's using, but it's not my decision.) I don't want anything changed on _my_ car. I was just wondering if there is a difference between tires with thin sidewalls and those with very wide sidewalls when it comes to odometer/speedometer readings. And I'm not talking about one inch differences, more like 45s vs. 85s. After you guys work out all this technical minutia let me know what the consensus is. The short answer is, no, there is no difference. The long asnwer is that the overall diameter has to be the same for the short answer to be true. For example, my truck has a 265/75x16. I could go to a 265/35x20 and the tire should be the same overall diameter, therefore no affect on the speedo. Supposing the two sizes have identical unloaded diameters, the 35 will have the larger rolling circumference and the slower speedometer reading. NOT true. Well, not entirely true. For every inch increase in the rim, the aspect ratio is decreased 5%. The result is a overall diameter, or radius, or circumference (depending on the specy you prefer) will be virtually identical. The difference -- if done on all four corners -- is insignificant. There will be a small change to the speedometer -- a change measured in single digit percentages. |
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The speedometer would be more sensitive to the circumference, but since circumference is calculated by diameter X pi, or radius X 2 X pi, then all are the same. I assume proper inflation, and ignore any argument that assumes improper inflation. Improper inflation causes a variance, and the variance is measured by the speed sensors, not the speedometer. |
#24
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"C. E. White" <cewhite3 (AT) mindspring (DOT) com> wrote in news:hcur0a$o5e$1 @news.eternal-september.org: How can what you are saying be true? Look at it a different way...every time the tire goes through a revolution, there is apporximately a one to one relationship between the tire and the road surface (every part of the tire contact the road). One revolution of the tire will move the car forward by the circumfrence of the tire. The /working/ circumference, which changes with all sorts of factors, pressure, weight, sidewall height. As I said before, ABS-based low-pressure warning systems _could not work_ unless this was true. |
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If it doesn't you have to have slip (which will be true if you spin the tires, but is a negligible factor if you are cruising straight ahead on a level road at a moderate sped). Not so. It's called "scrub" and is the reason tires wear even in a straight-ahead, steady-state position. The fact that the tire flattens out at the road surface doesn't change this. But that makes /all/ the difference. Of course rubber is flexible and can stretch/shrink, which is why the really important circumfrence is the circumfrence of the steel belts inside the tire. The treads area can stretch and flex (think about how tank treads move) but the steel belt stretchs only by tiny amounts. Unless the tire is so underinflated that the tire assumes a concave shape at the road surface, the effective rolling radius is not significantly dependednt on the distance from the road to the wheels center axis. Then how can an ABS-based warning system work if it cannot depend on changes in working radius? And monitoring changes in rolling circumference due to changed working radius _IS_ how such systems operate. |
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Like most real world things, there are other factors that come into play, so I don't doubt that there is some effect on revolutions per mile related to tires of the same outside diameter with different inner diameters (i.e., wheel size), but the I don't think the loaded radius is the prime reason. One more thing to think about. If you are right, where does the extra tire go? Where did that 1/4" go? I don't know. I suspect there's a minuscule stretch or displacement around the unloaded portion of the tire. But in order to confirm that, I'd need to jack the wheel off the ground and take some really careful measurements both loaded and unloaded. My contact patch is about 4.25" front-to-back (about 45deg of rotation). On my tire, a line traced from front-to-back on that flat spot is about a quarter-inch shorter than the curve would be if the tire was not flattened by the load. If that 1/4" were distributed evenly around the unloaded portion of my tire, each of the 315 degrees of unloaded tire would have to displace or stretch about .0008", which is plausible. Plus some of the distortion would be compressed into the flat spot, so the .0008 might be an overestimate. result inthe car moving forward by a distance equal to the loaded radius of the tire times 2 times pi. But the actual circumfrence of the tire is the unloaded diameter of the tire times pi. Since 2 times the loaded radius of the tire is less than the unloded diameter of the tire times pi, this implies something is happening witht he "extra" circumfrecne in your senario. Where is it going? You might convince me that the rubber portion is stretching and shrinking to accomodate your theory, but what is happenign with the steel belt in the tire? Well, I have one guess: The steel belt is a woven assembly with the wires on a bias. It's possible the weave distorts under compression and extension, much like rope, cloth or window screen can. One last analogy - think conveyor belt..... Did you look at the chart I included with the prior note? I did, but the chart misses the point. |
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My trump card is ABS-based low-pressure warning systems. I know for a fact that they work by sensing a low-pressure tire spinning faster than one with higher pressure, which can ONLY happen if the working radius (and circumference) can shrink and grow on an otherwise inextensible tire. |
#25
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"Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in news:hd05hr$6ok$1 (AT) news (DOT) eternal-september.org: "Tegger" <invalid (AT) invalid (DOT) inv> wrote in message news:Xns9CBAE381511EEtegger (AT) 208 (DOT) 90.168.18... "Jeff Strickland" <crwlrjeff (AT) yahoo (DOT) com> wrote in news:hd044q$sph$1 (AT) news (DOT) eternal-september.org: "badgolferman" <REMOVETHISbadgolferman (AT) gmail (DOT) com> wrote in message news:xn0ghaisbeui4k004 (AT) reader (DOT) albasani.net... Jeff Strickland wrote: The OP wants a larger sidewall for some reason, not a smaller one. (I don't get the logic he's using, but it's not my decision.) I don't want anything changed on _my_ car. I was just wondering if there is a difference between tires with thin sidewalls and those with very wide sidewalls when it comes to odometer/speedometer readings. And I'm not talking about one inch differences, more like 45s vs. 85s. After you guys work out all this technical minutia let me know what the consensus is. The short answer is, no, there is no difference. The long asnwer is that the overall diameter has to be the same for the short answer to be true. For example, my truck has a 265/75x16. I could go to a 265/35x20 and the tire should be the same overall diameter, therefore no affect on the speedo. Supposing the two sizes have identical unloaded diameters, the 35 will have the larger rolling circumference and the slower speedometer reading. NOT true. Well, not entirely true. For every inch increase in the rim, the aspect ratio is decreased 5%. The result is a overall diameter, or radius, or circumference (depending on the specy you prefer) will be virtually identical. The difference -- if done on all four corners -- is insignificant. There will be a small change to the speedometer -- a change measured in single digit percentages. As I said all along. The point is that it is unlikely that there will be NO change. Another example for illustration: Assume a tire with 23.21" diameter (my 195/60-14). The sidewall of that tire measures 4.6". The front tires drop about .875" at the contact patch. That's about 19%. Now assume a tire of the same diameter, but a hypothetical size of 195/35-18. This gives the sidewall a height of 2.7". Now imagine that this same tire has a drop of .875" at the contact patch. That's /one-third/ of the sidewall height of only 2.7"! NO 35-series tire drops 7/8" at the contact patch. It cannot. Any owner of that tire would be convinced his tire was flat! And this means the effective rolling circumference of such a tire would be /larger/ than the original 195/60-14, giving a slower speedometer reading.. The speedometer would be more sensitive to the circumference, but since circumference is calculated by diameter X pi, or radius X 2 X pi, then all are the same. I assume proper inflation, and ignore any argument that assumes improper inflation. Improper inflation causes a variance, and the variance is measured by the speed sensors, not the speedometer. If the wheel is turning at a speed other than what the speedometer is expecting, the speedometer will reflect that. Period. It may not be enough to notice in everyday driving, but it will be reflected. ABS-based speed sensors only track DIFFERENCES between wheels, not absolute speeds. And if a lower pressure makes a difference to the ABS, it will also make a difference to the speedometer, provided the lower pressure tire is on the wheel that's on the "solid" side of the diff. |
#26
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I am sure you are greatly over emphasizing the contribution of the loaded radius on the rolling diamter of tires, but don't know of any other effective arguements. Maybe an experiment would convince you. If you have the time, measure the loaded radius, mark the tire, move the car for 100 revolutions of the tire, and then measure the distance moved...You will find that it moved a significantly greater distance than 2 x pi x loaded radius x 100. |
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